LeapYear:

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   Determines if a year is a leap year

   Typing LeapYear returns the current leap year.

   Since version 1.
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   Form:
   ly = LeapYear( datetime )
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   ------
   Inputs
   ------
   datetime    (1,6) [year month day hour minute seconds] or just year

   -------
   Outputs
   -------
   ly          (1,1) 1 = yes, 0 = no

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Children:

Common: Time/DTSToDTA
Common: Time/Date2JD