InvP:
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The product form of the inverse:
[ 1 v1]-1
inv(Bnew) = [ 1 v2] inv(Bold)
[ v3]
v = inv(Bold)y where y is the new column k of B
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Form:
bInv = InvP( bInvOld, v, k )
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Inputs
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bInvOld (n,n) Old inverse
v (n,1) Vector = inv(Bold)*y where y is a new column of B
k Column index of v
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Outputs
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bInv (n,n) New inverse
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Children:
